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1/(1×2×3)+1/(2×3×4)+1/(3×4×5)+.+1/(98×99×100)=?
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人气:114 ℃ 时间:2020-05-05 02:53:08
解答
1/(1×2×3)+1/(2×3×4)+1/(3×4×5)+.+1/(98×99×100)=1/2 × [1/(1×2) - 1/(2×3) + 1/(2×3)-1/(3×4)+ 1/(3×4)-1/(4×5)+.+ 1/(98×99)-1/(99×100)]=1/2 × [1/(1×2) - 1/(99×100)]=1/2 × ...
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