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∫ (1,-1)xe^(x|x|)dx
人气:472 ℃ 时间:2020-04-16 15:41:33
解答
∫(-1,1)xe^(x|x|)dx
=∫(-1,0)xe^(-x^2)dx+∫(0,1)xe^x^2dx
=-1/2∫(-1,0)e^(-x^2)d(-x^2)+1/2∫(0,1)e^x^2dx^2
=1/2e^(-x^2)|[-1,0]+1/2e^x^2|[0,1]
=1/2[1-e^-1]+1/2[e-1]
=1/2[e-(1/e)]
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