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关于二次根式,
化简:
(√6+4√3+3√2)÷(√18+√12+3+√6)
人气:200 ℃ 时间:2020-05-04 09:46:20
解答
原式=(√3*√2+4*√3+√3*√6)/(√3*√6+√4*√3+√3*√3+√2*√3)
=(√2+4+√6)/(√6+2+√3+√2)
=(√2+2 +2 +√6)/(√6+√3 + 2+√2)
=[√2(√2+1)+√2(√2+√3)]/[√3(√2+1)+√2(√2+1)]
=[√2(√2+1)+√2(√2+√3)]/[(√3+√2)(√2+1)]
=√2/(√3+√2) + √2/(√2+1)
=√2(√3-√2)+√2(√2-1)
=√6-2+2-√2
=√6-√2
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