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分解因式:x2+2(a+1)x+2a+1.b2+c2+2ab+2ac+2bc
人气:230 ℃ 时间:2020-04-06 21:23:12
解答
x2+2(a+1)x+2a+1
=x²+2ax+2x+2a+1
=(x²+2x+1)+(2ax+2a)
=(x+1)²+2a(x+1)
=(x+1)(x+2a+1)


b2+c2+2ab+2ac+2bc
=(b²+2bc+c²)+(2ab+2ac)
=(b+c)²+2a(b+c)
=(b+c)(2a+b+c)

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