已知在△ABC与△A1B1C1中,AB=A1B1,BC=B1C1,∠BAC=∠B1A1C1=100°,求证:△ABC≌△A1B1C1
(2)若将上题中的100°改为70°,结论是否仍成立?为什么捏?
人气:124 ℃ 时间:2019-09-20 09:59:15
解答
过点A做AD⊥BA,过A1做A1D1⊥B1A1则在Rt△ABD和Rt△A1B1D1中AB=A1B1 ∠BAD=∠B1A1D1 AD=A1D1 ∴Rt△ABD≌Rt△A1B1D1 SAS∵Rt△ABD≌Rt△A1B1D1 ∴∠BAD=∠B1A1D1 ∠BAC=∠B1A1C1=100° ∴∠CAD=∠C1A1D1=10°又∵∠AB...
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