find an equation for a line that is normal to the graph of y = xe^x and goes
人气：422 ℃ 时间：2020-04-04 02:58:24
解答
找y'x
然后y'x是slope,因为normal垂直perpendicular,所以y1 times y2 equal to -1,
then find the value of y2(the normal one),
然后再代入随便一个数到原始y 得出(x,y）坐标,代入y2（normal）得出
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