求不定积分.∫【 u^(1/2)+1】(u-1) du:
人气:137 ℃ 时间:2020-01-29 19:20:39
解答
∫【 u^(1/2)+1】(u-1) du
=∫[ u^(3/2)+u-u^(1/2)-1)] du
=∫ u^(3/2)du+∫udu-∫u^(1/2)du-∫1 du
=2/5u^(5/2)+1/2u^2-2/3u^(3/2)-u+C
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