已知,x²+y²+4x-6y+13 = (x+2)²+(y-3)² = 0 ,因为,(x+2)² ≥ 0 ,(y-3)² ≥ 0 ,所以,(x+2)² = 0 ,(y-3)² = 0 ,可得：x+2 = 0 ,y-3 = 0 ,解得：x = -2 ,y = 3 ,所以,x^y = (-2...