思路：代数式x-(x-1)/2与(x+2)/5-2的值互为相反数,【x-(x-1)/2】+【(x+2)/5-2】=0,转化为一元一次方程问题【x-(x-1)/2】+【(x+2)/5-2】=010x-5(x-1)+2(x+2)-20=010x-5x+5+2x+4-20=010x-5x+2x=20-5-47x=11x=11/7...