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设x-y-z=19,x2+y2+z2=19,则yz-zx-xy=______.
人气:393 ℃ 时间:2020-06-01 01:29:39
解答
将x-y-z=19两边平方得:
(x-y-z)2=361,即x2+y2+z2-2xy-2xz+2yz=361,
∵x2+y2+z2=19,
∴x2+y2+z2-2xy-2xz+2yz=19+2(yz-xy-xz)=361,
则yz-xy-xz=
361−19
2
=171.
答案为:171.
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