已知代数式(3a2-ab+2b2)-(a2-5ab+b2)-2(a2+2ab+b2).
(1)试说明这个代数式的值与a的取值无关;
(2)若b=-2,求这个代数式的值.
人气:324 ℃ 时间:2019-08-21 22:19:36
解答
(1)(3a2-ab+2b2)-(a2-5ab+b2)-2(a2+2ab+b2)
=3a2-ab+2b2-a2+5ab-b2-2a2-4ab-2b2
=3a2-a2-2a2-ab+5ab-4ab+2b2-b2-2b2
=-b2;
因为原代数式化简后的值为-b2,不含字母a,所以这个代数式的值与a的取值无关.
(2)当b=-2时,原式=-b2=-(-2)2=-4.
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