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数学
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(-32又16/25)×(1/32)-(1/2+2/3-3/4-11/12)×(-24)求过程
人气:283 ℃ 时间:2020-05-28 22:46:22
解答
(-32又16/25)×(1/32)-(1/2+2/3-3/4-11/12)×(-24)
=(-32-16/25)×(1/32)+(1/2+2/3-3/4-11/12)×24
=-1-1/50+12+16-18-22
=-13又1/50
推荐
-32又25分之16/(-8*4)+(2分之1+3分之2-4分之3-12分之11)*24,
-32又25分之16÷(-8×4)+2.5²+(1/2+2/3-3/4-11/12)×24
负32又16/25*负1/32-(1/2+2/3-3/4-11/12)*负24
-32又16/25÷(-8×4)+2.5²+(1/2+2/3-3/4-11/12)×24,
-32又16/25÷(-8×4)+2.5²+(1/2+2/3-3/4-11/12)×24过程
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