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已知 x^2+xy+y^2=20 3xy+x-y=-22 求x-y的值
人气:247 ℃ 时间:2020-06-21 14:49:24
解答
x^2+xy+y^2=203xy+x-y=-22
x^2+xy+y^2-(3xy+x-y)=20-(-22)
即x^2-2xy+y^2-(x-y)=42
(x-y)^2-(x-y)=42
(x-y)^2-(x-y)-42=0
(x-y-7)(x-y+6)=0
x-y=7或x-y=-6
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