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化简sin^4x-sin^2+cos^2
化简(1)sin^4x-sin^2+cos^2
(2)根号(1+cosα/1-cosα)+根号(1-cosα/1+cosα)(180°<α<270°)
人气:377 ℃ 时间:2020-06-06 19:15:19
解答
(1) (sinx)^4 - (sinx)^2 + (cosx)^2
=(1-cos2x)^2/4 + cos2x
= [ 1 - 2 cos2x + (cos2x)^2 + 4 cos2x ] / 4
= ( 1 + cos2x )^2 /4
= [ ( 1 + cos2x ) / 2 ]^2
= (cosx)^4
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