已知弧长求半径 弧长C=540 弦长L=492 半径R是多少呢?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=300
R1=342.23
R2=361.57
R3=364.61
R4=364.68
R5=364.68
R=364.68