已知函数f(x)=sin(x+2分之派)sin(x-2x)1:求函数f(x)的最值和最小正周期 2:计算f(6分之派+f(12分之派)
人气:266 ℃ 时间:2020-06-16 12:51:19
解答
f(x)=sin(x+π/2)sin(x-2π).
=cosx(-sinx).
=-sinxcosx.
=-(1/2)sin2x.
1) ∵-1≤sin2x≤1,
∴f(x)max=-(1/2)*(-1)=1/2.
f(x)min=-(1/2)*1=-1/2.
最小正周期T=2π/2=π ;
2)f(π/6)+f(π/12)=-(1/2)[sin2*(π/6)+sin2*(π/12)].
=-√3/4-1/4.
=-(1/4)(√3+1)
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