x=√2-√3y=1/(√3-√2)=(√3+√2)/(√3+√2)(√3-√2)=(√3+√2)/(3-2)=√3+√2x²-xy+y²=(x-y)²+xy=(√2-√3-√3-√2)²+(√2-√3)(√3+√2)=(-2√3)²+2-3=12-1=11