[(x-2)分之3x-(x+2)分之x]×x分之(x²-4)
=[(x-2)分之3x-(x+2)分之x]×x分之[(x+2)(x-2)]
=(x-2)分之3x×x分之[(x+2)(x-2)]-(x+2)分之x×x分之[(x+2)(x-2)]
=3(x+2)-(x-2)
=3x+6-x+2
=2x+8
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