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把6x(x-y)的平方+3(y-x)的立方分解因式
我知道答案是6x(x-y)^2+3(y-x)^3
=6x(x-y)^2-3(x-y)^3
=3(x-y)^2[2x-(x-y)]
=3(x-y)^2(x+y)可为什么=6x(x-y)^2-3(x-y)^3
=3(x-y)^2[2x-(x-y)]
人气:296 ℃ 时间:2020-04-03 20:08:04
解答
提取公因式3(x-y) ^2,那么 6x(x-y)^2还剩下2x,3(x-y)^ 3 还剩下(x-y).详细应该是这样:将 6x(x-y)^2看做2x乘以 3(x-y) ^2.同样,讲 3(x-y)^ 3看做(x-y) 乘以[3(x-y) ^2]
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