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xy2-2xy-3x-y2-2y-1
因式分解.
人气:440 ℃ 时间:2020-01-30 08:47:17
解答
xy2-2xy-3x-y2-2y-1
=(xy2-2xy-3x)-(y2+2y+1)
=x(y2-2y-3)-(y+1)2
=x(y+1)(y-3)-(y+1)平方
=(y+1)[x(y-3)-y-1]
=(y+1)(xy-3x-y-1)
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