很高兴喂你解答!
原式=4√[(x^2+xy+y^2)/(x-y)*1/2√[(x^2-xy+y^2)/(x+y)*3√(x^3+y^3)
=6√[(x^2+xy+y^2)/(x-y)*√[(x^2-xy+y^2)/(x+y)*√[(x+y)*（x^2-xy+y^2)]
=6(x^2-xy+y^2)*√[(x^+xy+y^2)/(x-y)]
=6[(x^2-xy+y^2)/(x-y)]*√(x^3+y^3)
好了,希望对你有所帮助哦!那个你做错了不好意思！！！尽力了！！！