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关于sin,cos,tan,cot,csc,sec
coty-tany
----------=csc的二次方y-sec的二次方y
sinycosy
人气:190 ℃ 时间:2020-05-13 21:11:01
解答
(coty-tany)/(sinycosy)
=(cosy/siny-siny/cosy)/sinycosy
=(cos^2y-sin^2y)/sin^2yos^2y
=1/sin^2y-1/cos^2y
=csc^2y-sec^2y
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