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化简 (m-n)/(m+2n)+(m^2-n^2)/(m^2+4mn+4n^2)
人气:231 ℃ 时间:2020-06-23 09:06:03
解答
(m-n)/(m+2n)+(m^2-n^2)/(m^2+4mn+4n^2)= (m-n)/(m+2n)+(m-n)(m+n)/(m+2n)^2=[(m-n)(m+2n)+(m-n)(m+n)]/(m+2n)^2=(m-n)(m+2n+m+n)/(m+2n)^2=(m-n)(2m+3n)/(m+2n)^2
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