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计算:1.(-1/2)的-2次方×0.125+2009的0次方+|-1| 2.x²/(x-1)-1-x 3.(1-(2/x+1)²÷x-1/x+1
人气:327 ℃ 时间:2019-08-20 04:34:19
解答
1.(-1/2)的-2次方×0.125+2009的0次方+|-1|=4×0.125+1+1=2.5 2.x²/(x-1)-1-x=x²/(x-1)-(x+1)(x-1)/(x-1)=(x²-x²+1)/(x-1)=1/(x-1) 3.(1-(2/x+1)²÷x-1/x+1 =1-4/(x+1)²...
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