计算:(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)
人气：178 ℃ 时间：2020-03-24 20:21:21
解答
(1)当x不等于1 (x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1) =[(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)]/(x-1) =[(x^2-1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)]/(x-1) =[(x^4-1)(x^4+1)(x^8+1)(x^16+1)(...
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