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二元一次方程组怎么解 2/3(x-y)-(x+y)=-1 6x+y-(2x-y)=16
2/3(x-y)-(x+y)=-1
6x+y-(2x-y)=16
人气:204 ℃ 时间:2020-03-30 11:14:04
解答
2/3(x-y)-(x+y)=-1
2x-3y-3x-3y=-3
x+6y=3 (1)
6x+y-(2x-y)=16
5x+y-2x+y=16
3x+2y=16 (2)
(2)×3-(1)
9x-x=48-3
8x=45
所以x=45/8
y=(16-3x)/2=-7/16不是3乘2是 3分之二2/3(x-y)-(x+y)/4=-16x+y-(2x-y)=16哦,对不起,我做错了2/3(x-y)-(x+y)=-1两边乘32x-2y-3x-3y=-3x+5y=3 (1)6x+y-(2x-y)=166x+y-2x+y=162x+y=8 (2)(1)×2-(2)10y-y=6-89y=-2所以y=-2/9x=3-5y=37/9不对是这个题2/3(x-y)-(x+y)/4=-16x+y-(2x-y)=16那是你写错了采纳我,重新问哦算了2/3(x-y)-(x+y)/4=-1两边乘128x-8y-3x-3y=-125x-11y=-12 (1)6x+y-(2x-y)=164x+2y=16所以2x+y=8y=8-2x代入(1)5x-88+22x=-1227x=76x=76/27y=8-2x=64/27
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