1/(x+1)+2/(x-2)=8/(x²-4)
两边同乘以(x+1)(x²-4),得
x²-4+2(x+1)(x+2)=8(x+1)
3x²-2x-1=0
(3x+1)(x-1)=0
x1=-1/3
x2=1
经检验,知以上两个都是原方程的解