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数学
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点(m,n)关于直线ax+by+c=0的对称点是多少
人气:373 ℃ 时间:2020-05-26 21:09:10
解答
设A(m,n),B(p,q),则AB的斜率为(q-n)/(p-m),又直线Ax+By+C=0的斜率为-A/B,由于AB与直线Ax+By+C=0互相垂直,所以可得一个关于p和q的方程:(q-n)/(p-m)×[-A/B]=-1;AB的中点为((p+m)/2,(q+n)/2),这个中点在直线Ax...
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