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(1)sin^2a+sin^2b-sin^2a*sin^2b+cos^2a*cos^2b
(2) tana*(cosa-sina)+sina*(sina+tana)/(1+cosa)
人气:317 ℃ 时间:2020-05-28 09:16:20
解答
1)sin^2a+sin^2b-sin^2a*sin^2b+cos^2a*cos^2b
=(sin^2a-sin^2a*sin^2b)+sin^2b+cos^2a*cos^2b
=(sin^2a*cos^2b+cos^2a*cos^2b)+sin^2b
=cos^2b+sin^2b
=1
2) tana*(cosa-sina)+sina*(sina+tana)/(1+cosa)
tana*(cosa-sina)=sina-sin^2a/cosa
sina*(sina+tana)/(1+cosa)=sin^2a*(1+1/cosa)/(1+cosa)=sin^2a/cosa
所以 原式=sina
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