解不等式(x-1)(x-2)(x-3)(x-4)>120
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人气:359 ℃ 时间:2020-04-19 21:41:14
解答
(x-1)(x-2)(x-3)(x-4)>120(x-1)(x-4)(x-2)(x-3)>120(x^2-5x+4)(x^2-5x+6)>120(x^2-5x)^2+10(x^2-5x)+24-120>0(x^2-5x)^2+10(x^2-5x)-96>0(x^2-5x+16)(x^2-5x-6)>0因为x^2-5x+16>0恒成立所以x^2-5x-6>0(x-6)(x+1)>0x6...
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