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分式的加减:(x-3/x²+6x+9)+(x/9-x²)
人气:364 ℃ 时间:2020-03-21 03:32:11
解答
(x-3)/(x+3)^2+x/(3+x)(3-x)
=[(x-3)^2-x(x+3)]/(x+3)^2(x-3)
=(x^2-6x+9-x^2-3x)/(x+3)^2(x-3)
=(-9x+9)/(x+3)^2(x-3)
=9(1-x)/(x+3)^2(x-3)
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