化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π_数学解答

化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)

人气：324 ℃　时间：2020-10-01 22:15:09

解答

原式
=sin(-α)(-cosα)(-sinα)/(-cosα)sinαsinαcosα
=-sinαcosαsinα/(-cosαsinαsinαcosα)
=1/cosα