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(1)3/2 乘 cosx - √3/2 乘sinx;
(2)√3乘sinx/2+cosx/2;
(3)√2/4 乘sin(π/4 - x)+√6/4 乘cos(π/4 - x);
人气:182 ℃ 时间:2020-01-28 00:12:14
解答
(1)3/2 乘 cosx - √3/2 乘sinx
=√3(√3/2 乘 cosx - 1/2 乘sinx)
=√3( cos30乘 cosx - sin30乘sinx)
=√3cos(30+x)
(2)√3乘sinx/2+cosx/2=2(√3/2乘sinx/2+1/2cosx/2)=2sin(x/2+30)
(3)√2/4 乘sin(π/4 - x)+√6/4 乘cos(π/4 - x)
=√2/2(cos60sin(π/4 - x)+sin60cos(π/4 - x))
=√2/2sin(7π/12-x)
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