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因式分解x^3+3x^2y+2xy^2
人气:468 ℃ 时间:2020-01-28 19:42:49
解答
原式=(x^3+x²y)+(2x²y+2xy²)[将3x²y拆成两项]
=x²(x+y)+2xy(x+y)
=(x+y)(x²+2xy)
=x(x+y)(x+2y)
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