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计算:[(4x^3-1/2y)^2+4y(x^2-y/16)]/(8x^2)
人气:492 ℃ 时间:2020-01-29 09:54:19
解答
:[(4x^3-1/2y)^2+4y(x^2-y/16)]/(8x^2)
=(16x^6-4x^3y²+1/4y²+4x²y-1/4y²)/(8x²)
=2x^4-1/2xy²+1/2y
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