很高兴为您(x²-4X+4分之x²-4+x+2分之2-x)除以x-2分之x [(x²-4)/（x²-4x+4)+(2-x)/(x+2)]÷[x/(x-2)]=[(x-2)(x+2)/(x-2)²+(2-x)/(x+2）]×(x-2)/x=[(x+2)/(x-2)+(2-x)/(x+2)]×(x-2)/x={[(x...=[(x-2)(x+2)/(x-2)²+(2-x)/(x+2）]×(x-2)/x ?={[(x+2)²-(x-2)²]/(x²-4)}×(x-2)/x ?=8x/[(x-2)(x+2)]*(x-2)/x?ԭʽ={(x+2)/(x-2)+(2-x)/(x+2)}x(x-2)/x=��x+2��\x-(x-2)^2/x(x+2) = 8x/x(x+2)==8/(x+2)还是不懂原式={(x+2)/(x-2)+(2-x)/(x+2)}x(x-2)/x=（x+2）\x-(x-2)^2/x(x+2)= 8x/x(x+2)==8/(x+2) 是什么的��һ������ԭʽ={(x+2)/(x-2)+(2-x)/(x+2)}x(x-2)/x=��x+2��\x-(x-2)^2/x(x+2)= 8x/x(x+2)==8/(x+2) �ǽ����ĵ�[(x-2)(x+2)/(x-2)²+(2-x)/(x+2）]×(x-2)/x 这个��={[(x+2)²-(x-2)²]/(x²-4)}��(x-2)/x ? =8x/[(x-2)(x+2)]*(x-2)/x?��={[(x+2)²-(x-2)²]/(x²-4)}×(x-2)/x =8x/[(x-2)(x+2)]*(x-2)/x =8/(x+2)=8x/[(x-2)(x+2)]*(x-2)/x=8/(x+2)都等于8/(x+2)。