f(x)的定义域是[0,1]
所以对于函数y=f[log1/2(3-x)]
log1/2(3-x)必须在[0,1]内取值
0≤log1/2(3-x)≤1
log1/2 1≤log1/2(3-x)≤log1/2 1/2
1/2≤3-x≤1
-1≤x-3≤-1/2
2≤x≤5/2
函数y=f[log1/2(3-x)]的定义域是[2,5/2]