是求原函数吧.
∫ x(sin2x-sinx) dx
= ∫ xsin2x dx - ∫ xsinx dx
= -1/2∫ xdcos2x + ∫ x dcosx
= -1/2(xcos2x - ∫ cos2x dx) + xcosx - ∫ cosx dx
= -1/2(xcos2x - sin2x/2) + xcosx - sinx