^ 表示乘方原式=[2x^(n+2)-6x^(3n-1)+10x^4n]÷[(1/2)x^n]=[2x^(n+2)]÷[(1/2)x^n]-[6x^(3n-1)]÷[(1/2)x^n]+[(10x^4n)÷[(1/2)x^n]=[(2÷1/2)×x^(n+2)÷x^n]-[(6÷1/2)×x^(3n-1)÷x^n]+[(10÷1/2)×x^4n÷x^n]=4...