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因式分解:a^2×b^2-4ab-5
x^4+6x^2+8
(x+y)^2-3(x+y)+2
人气:470 ℃ 时间:2020-05-24 15:14:46
解答
a^2×b^2-4ab-5
=(ab-5)(ab+1)
x^4+6x^2+8
=(x²+2)(x²+4)
(x+y)^2-3(x+y)+2
=[(x+y)-1][(x+y-2]
=(x+y-1)(x+y-2)
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