(Lg4-Lg60)/(Lg3+Lg5)
=Lg(4/60)/Lg(3*5)
=Lg(1/15)/Lg15
=Lg15^(-1)/Lg15
=-Lg15/Lg15
=-1
(4^5)*[2^(-11)]
=(2^2)^5*2^(-11)
=2^(2*5-11)
=2^(-1)
=1/2
所以[(Lg4-Lg60)/(Lg3+Lg5)]^3-(4^5)*[2^(-11)]
=（-1）^3-1/2
=-1-1/2
=-3/2