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cos2a/sin(a-pai/4)=-根号2/2求cosa+sina
人气:116 ℃ 时间:2019-10-08 22:52:42
解答
cos2a/sin(a-pai/4)=-根号2/2
cos2a/(sinacos(pai/4)-cosasin(pai/4))=-根号2/2
cos2a/(根号2/2*sina-根号2/2*cosa)=-根号2/2
cos2a/根号2/2*(sina-cosa)=-根号2/2
(cos^2 a-sin^2 a)/(sina-cosa)=-1/2
(cosa-sina)(cosa+sina)/(sina-cosa)=-1/2
cosa+sina=1/2.
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