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数学
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计算(㏒5)2+㏒10(2)×㏒10﹙50﹚+㏒2﹙32﹚
人气:478 ℃ 时间:2020-07-10 11:19:13
解答
=lg5+lg2×(lg5+lg10)+log2(2^5)
=lg5+lg2×(lg5+1)+5log2(2)
=lg5+lg2×lg5+lg2+5
=(lg5+lg2)+lg2×lg5+5
=1+lg2×lg5+5
=6+lg2×lg5
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