求导数:y=[sin(x/2)+cos(x/2)]^2-1
人气:385 ℃ 时间:2019-08-31 18:57:27
解答
y=(sinx/2)^2+2sinx/2cosx/2+(cosx/2)^2-1
=1+sinx-1=sinx,
y'=cosx.
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