∫5/(t+3)(t-2)dt积分上限为0 下限为1=∫[(t+3)-(t-2)]/(t+3)(t-2)dt]积分上限为0 下限为1=∫[1/(t-2) -1/(t+3)]dt积分上限为0 下限为1=ln|t-2|-ln|t+3| 0→1=ln...