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向10mL0.01mol/LBaCl2溶液中加入10mL0.01mol/LH2SO4溶液,反应后溶液的ph为
人气:248 ℃ 时间:2020-01-28 17:33:49
解答
c(H+) = 2n(H2SO4)/V(混合后的体积) = 2*0.01*0.01/0.02 = 0.01 mol/L
PH = -lg c(H+) = -lg0.01 = 2n是指硫酸物质的量么?对啊,n(H2SO4)=c(H2SO4)*V(H2SO4)
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