答：∫In(x+a)/(x+b)dx=∫[(In(x+a)-In(x+b)]dx=∫In(x+a)dx-∫In(x+b)dx=(x+a)[In(x+a)-1]-(x+b)[In(x+b)-1]+C=(x+a)In(x+a)-(x+b)In(x+b)+b-a+CC是常数.这里说一下,∫In(x+a)dx=∫In(x+a)(x)'dx=xIn(x+a)-∫{[In(x...