(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2 ）=?不好意思啊,发错题了.是除以(-1/_数学解答

(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2 ）=?不好意思啊,发错题了.是除以(-1/2x^3y^2）

人气：328 ℃　时间：2020-02-04 05:23:58

解答

(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2)
=-(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)*(2x^3y^2)
=1/2xy+1/xy^2+1/3
=(3y+6+2xy^2)/(6xy^2)
1/4等都是系数
则
(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2)
=-1/2*xy+xy^3+1/3