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2x-6/(4-4x+x^2)*(x^2+x-6)/(12-4x)/(x+3)
人气:498 ℃ 时间:2020-09-06 03:16:27
解答
(2x-6)/(4-4x+x²)×(x²+x-6)/(12-4x)/(x+3)=[2(x-3)/(x-2)²]×(x+3)(x-2)×1/4(3-x)×1/(x+3)=-[2(x-3)/(x-2)²]×(x+3)(x-2)×1/4(x-3)×1/(x+3)=1/2(x-2)
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