已知x的相反数为y-6,y的倒数为2x,求出代数式(5xy+4x+7y)+3(2x-xy)-(4xy-3y)的值
已知x的相反数为y-6,y的倒数为2x,求出代数式(5xy+4x+7y)+3(2x-xy)-(4xy-3y)的值
人气：110 ℃ 时间：2020-02-06 00:19:54
解答
x的相反数为y-6,y的倒数为2x
x+y=6 2xy=1
(5xy+4x+7y)+3(2x-xy)-(4xy-3y)
=5xy+4x+7y+6x-3xy-4xy+3y
=-2xy+10x+10y
=10(x+y)-2xy
=60-1
=59
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